importlib.resources
– Package resource reading, opening and access¶
Source code: Lib/importlib/resources/__init__.py
Added in version 3.7.
This module leverages Python’s import system to provide access to resources within packages.
«Resources» are file-like resources associated with a module or package in Python. The resources may be contained directly in a package, within a subdirectory contained in that package, or adjacent to modules outside a package. Resources may be text or binary. As a result, Python module sources (.py) of a package and compilation artifacts (pycache) are technically de-facto resources of that package. In practice, however, resources are primarily those non-Python artifacts exposed specifically by the package author.
Resources can be opened or read in either binary or text mode.
Resources are roughly akin to files inside directories, though it’s important
to keep in mind that this is just a metaphor. Resources and packages do
not have to exist as physical files and directories on the file system:
for example, a package and its resources can be imported from a zip file using
zipimport
.
Примітка
This module provides functionality similar to pkg_resources Basic Resource Access without the performance overhead of that package. This makes reading resources included in packages easier, with more stable and consistent semantics.
The standalone backport of this module provides more information on using importlib.resources and migrating from pkg_resources to importlib.resources.
Loaders
that wish to support resource reading should implement a
get_resource_reader(fullname)
method as specified by
importlib.resources.abc.ResourceReader
.
- class importlib.resources.Anchor¶
Represents an anchor for resources, either a
module object
or a module name as a string. Defined asUnion[str, ModuleType]
.
- importlib.resources.files(anchor: Anchor | None = None)¶
Returns a
Traversable
object representing the resource container (think directory) and its resources (think files). A Traversable may contain other containers (think subdirectories).anchor is an optional
Anchor
. If the anchor is a package, resources are resolved from that package. If a module, resources are resolved adjacent to that module (in the same package or the package root). If the anchor is omitted, the caller’s module is used.Added in version 3.9.
Змінено в версії 3.12: package parameter was renamed to anchor. anchor can now be a non-package module and if omitted will default to the caller’s module. package is still accepted for compatibility but will raise a
DeprecationWarning
. Consider passing the anchor positionally or usingimportlib_resources >= 5.10
for a compatible interface on older Pythons.
- importlib.resources.as_file(traversable)¶
Given a
Traversable
object representing a file or directory, typically fromimportlib.resources.files()
, return a context manager for use in awith
statement. The context manager provides apathlib.Path
object.Exiting the context manager cleans up any temporary file or directory created when the resource was extracted from e.g. a zip file.
Use
as_file
when the Traversable methods (read_text
, etc) are insufficient and an actual file or directory on the file system is required.Added in version 3.9.
Змінено в версії 3.12: Added support for traversable representing a directory.
Deprecated functions¶
An older, deprecated set of functions is still available, but is scheduled for removal in a future version of Python. The main drawback of these functions is that they do not support directories: they assume all resources are located directly within a package.
- importlib.resources.Package¶
Whenever a function accepts a
Package
argument, you can pass in either amodule object
or a module name as a string. You can only pass module objects whose__spec__.submodule_search_locations
is notNone
.The
Package
type is defined asUnion[str, ModuleType]
.Застаріло починаючи з версії 3.12.
- importlib.resources.Resource¶
For resource arguments of the functions below, you can pass in the name of a resource as a string or a
path-like object
.The
Resource
type is defined asUnion[str, os.PathLike]
.
- importlib.resources.open_binary(package, resource)¶
Open for binary reading the resource within package.
package is either a name or a module object which conforms to the
Package
requirements. resource is the name of the resource to open within package; it may not contain path separators and it may not have sub-resources (i.e. it cannot be a directory). This function returns atyping.BinaryIO
instance, a binary I/O stream open for reading.Застаріло починаючи з версії 3.11: Calls to this function can be replaced by:
files(package).joinpath(resource).open('rb')
- importlib.resources.open_text(package, resource, encoding='utf-8', errors='strict')¶
Open for text reading the resource within package. By default, the resource is opened for reading as UTF-8.
package is either a name or a module object which conforms to the
Package
requirements. resource is the name of the resource to open within package; it may not contain path separators and it may not have sub-resources (i.e. it cannot be a directory). encoding and errors have the same meaning as with built-inopen()
.This function returns a
typing.TextIO
instance, a text I/O stream open for reading.Застаріло починаючи з версії 3.11: Calls to this function can be replaced by:
files(package).joinpath(resource).open('r', encoding=encoding)
- importlib.resources.read_binary(package, resource)¶
Read and return the contents of the resource within package as
bytes
.package is either a name or a module object which conforms to the
Package
requirements. resource is the name of the resource to open within package; it may not contain path separators and it may not have sub-resources (i.e. it cannot be a directory). This function returns the contents of the resource asbytes
.Застаріло починаючи з версії 3.11: Calls to this function can be replaced by:
files(package).joinpath(resource).read_bytes()
- importlib.resources.read_text(package, resource, encoding='utf-8', errors='strict')¶
Read and return the contents of resource within package as a
str
. By default, the contents are read as strict UTF-8.package is either a name or a module object which conforms to the
Package
requirements. resource is the name of the resource to open within package; it may not contain path separators and it may not have sub-resources (i.e. it cannot be a directory). encoding and errors have the same meaning as with built-inopen()
. This function returns the contents of the resource asstr
.Застаріло починаючи з версії 3.11: Calls to this function can be replaced by:
files(package).joinpath(resource).read_text(encoding=encoding)
- importlib.resources.path(package, resource)¶
Return the path to the resource as an actual file system path. This function returns a context manager for use in a
with
statement. The context manager provides apathlib.Path
object.Exiting the context manager cleans up any temporary file created when the resource needs to be extracted from e.g. a zip file.
package is either a name or a module object which conforms to the
Package
requirements. resource is the name of the resource to open within package; it may not contain path separators and it may not have sub-resources (i.e. it cannot be a directory).Застаріло починаючи з версії 3.11: Calls to this function can be replaced using
as_file()
:as_file(files(package).joinpath(resource))
- importlib.resources.is_resource(package, name)¶
Return
True
if there is a resource named name in the package, otherwiseFalse
. This function does not consider directories to be resources. package is either a name or a module object which conforms to thePackage
requirements.Застаріло починаючи з версії 3.11: Calls to this function can be replaced by:
files(package).joinpath(resource).is_file()
- importlib.resources.contents(package)¶
Return an iterable over the named items within the package. The iterable returns
str
resources (e.g. files) and non-resources (e.g. directories). The iterable does not recurse into subdirectories.package is either a name or a module object which conforms to the
Package
requirements.Застаріло починаючи з версії 3.11: Calls to this function can be replaced by:
(resource.name for resource in files(package).iterdir() if resource.is_file())